Question
If the probability distribution of a random variable X is given below:
X = Xi 1 2 3 4
P(X = Xi) c 2c 4c 4c
Write the value of $\text{P}(\text{X}\leq2)$

Answer

We know that the sum of probabilities in a probability distribution is always 1.
Therefore,
P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 1
⇒ c + 2c + 4c + 4c =1
⇒ 11c = 1
$\Rightarrow\text{c}=\frac{1}{11}$
Now,
$\text{P}(\text{X}\leq2)=\text{P}(\text{X}=1)+\text{P}(\text{X})=2=\frac{1}{10}+\frac{2}{10}=\frac{3}{10}$

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