MCQ
If the roots of the equation $a{x^2} + bx + c = 0$be $\alpha $and $\beta $, then the roots of the equation $c{x^2} + bx + a = 0$ are
  • A
    $ - \alpha , - \beta $
  • B
    $\alpha ,\frac{1}{\beta }$
  • $\frac{1}{\alpha },\frac{1}{\beta }$
  • D
    None of these

Answer

Correct option: C.
$\frac{1}{\alpha },\frac{1}{\beta }$
c
(c) $\alpha ,\beta $are roots of $a{x^2} + bx + c = 0$

==> $\alpha + \beta = - \frac{b}{a}$ and $\alpha \beta = \frac{c}{a}$

Let the roots of $c{x^2} + bx + a = 0$be $\alpha ',\beta '$, then

$\alpha ' + \beta ' = - \frac{b}{c}$and $\alpha '\beta ' = \frac{a}{c}$

but $\frac{{\alpha + \beta }}{{\alpha \beta }} = \frac{{ - b/a}}{{c/a}} = \frac{{ - b}}{c}$

==>$\frac{1}{\alpha } + \frac{1}{\beta } = \alpha ' + \beta '$

Hence $\alpha ' = \frac{1}{\alpha }$ and $\beta ' = \frac{1}{\beta }$.

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