If the roots of the given equation 2 x^2 + 3( - 2)x + + 4 = 0 be … - Vidyadip

Question

If the roots of the given equation $2{x^2} + 3(\lambda - 2)x + \lambda + 4 = 0$ be equal in magnitude but opposite in sign, then $\lambda $=

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Answer

b
(b) Let roots are $\alpha $and $ - \alpha $, then sum of the roots

$\alpha + ( - \alpha ) = \frac{{3(\lambda - 2)}}{2}$

$\Rightarrow 0 = \frac{3}{2}(\lambda - 2)$

==>$\lambda = 2$

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