MCQ
If the roots of the given equation $2{x^2} + 3(\lambda - 2)x + \lambda + 4 = 0$ be equal in magnitude but opposite in sign, then $\lambda $=
- A$1$
- ✓$2$
- C$3$
- D$2/3$
$\alpha + ( - \alpha ) = \frac{{3(\lambda - 2)}}{2}$
$\Rightarrow 0 = \frac{3}{2}(\lambda - 2)$
==>$\lambda = 2$
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