MCQ
If the roots of ${x^2} + x + a = 0$exceed $a$, then
- A$2 < a < 3$
- B$a > 3$
- C$ - 3 < a < 3$
- ✓$a < - 2$
Therefore, if the roots of ${x^2} + x + a = 0$ exceed a number a, then
${a^2} + a + a > 0,1 - 4a \ge 0$ and $ - 1 > 2a$
==> $a(a + 2) > 0,$$a \le \frac{1}{4}$and $a < - \frac{1}{2}$
==> $a > 0\,{\rm{or}}\,a < - 2,a < \frac{1}{4}$and $a < - \frac{1}{2}$
Hence $a < - 2$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.