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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
If the solubility product ${K_{sp}}$ of a sparingly soluble salt $M{X_2}$ at $25\,^oC$ is $1.0 \times {10^{ - 11}}$, the solubility of the salt in mole litre$^{-1}$ at this temperature will be
  • A
    $2.46 \times {10^{14}}$
  • ✓
    $1.36 \times {10^{ - 4}}$
  • C
    $2.60 \times {10^{ - 7}}$
  • D
    $1.20 \times {10^{ - 10}}$
✓

Answer

Correct option: B.
$1.36 \times {10^{ - 4}}$
(b) $M{X_2}⇌ \mathop {{M^ + }}\limits_{(S)\,\,\,} + \mathop {2{X^ - }}\limits_{{{(2S)}^2}\,\,} $;

${K_{sp}} = 4{S^3}$

$S = \sqrt[3]{{\frac{{{K_{sp}}}}{4}}} = \sqrt[3]{{\frac{{1 \times {{10}^{ - 11}}}}{4}}} = 1.35 \times {10^{ - 4}}$

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