MCQ
If the system of equation $2x + 3y =\, -1; 3x + y = 2; \lambda x + 2y = \mu $ is consistent, then
- ✓$\lambda - \mu = 2$
- B$\lambda + \mu = -1$
- C$\lambda + \mu = 3$
- D$\lambda - \mu + 8= 0$
$\mathrm{x}=1$ and $\mathrm{y}=-1$ put in equation $(3)$
$\lambda \mathrm{x}+2 \mathrm{y}=\mu \Rightarrow \lambda-2=\mu$
$\Rightarrow \quad \boxed{\lambda - \mu = 2}$
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$f(x) = max (4 -x^2, 1 + x^2), -2 < x < 0 $
$= min (4 -x^2, 1 + x^2), 0 < x < 2$.
The $f(x)$
$7 x+11 y+\alpha z=13$
$5 x+4 y+7 z=\beta$
$175 x+194 y+57 z=361$
has infinitely many solutions, then $\alpha+\beta+2$ is equal to