If the time period $t$ of the oscillation of a drop of liquid of density $d$, radius $r$, vibrating under surface tension $s$ is given by the formula $t = \sqrt {{r^{2b}}\,{s^c}\,{d^{a/2}}} $ . It is observed that the time period is directly proportional to $\sqrt {\frac{d}{s}} $ . The value of $b$ should therefore be
A$\frac{3}{4}$
B$\sqrt 3 $
C$\frac{3}{2}$
D$\frac{2}{3}$
JEE MAIN 2013, Diffcult
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C$\frac{3}{2}$
c $T=\sqrt{\left(M L^{-3}\right)^{a} r^{b}[M T^ {-2}] c}$
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