MCQ
If the two equations ${x^2} - cx + d = 0$ and ${x^2} - ax + b = 0$ have one common root and the second has equal roots, then $2(b + d) = $
- A$0$
- B$a + c$
- ✓$ac$
- D$ - ac$
$\alpha + \beta = c,\alpha \beta = d,\alpha + \alpha = a,{\alpha ^2} = b$
Hence $2(b + d) = 2({\alpha ^2} + \alpha \beta ) = 2\alpha (\alpha + \beta ) = ac$
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