- A$\alpha = \beta \ne \gamma $
- B$\alpha = \gamma \ne \beta $
- C$\beta = \gamma \ne \alpha $
- ✓$\alpha = \beta = \gamma $
${\cos ^{ - 1}}\left\{ {\frac{{(i + j + k)\,.\,i}}{{|i + j + k|\,\,|i|}}} \right\} \Rightarrow \alpha = {\cos ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} \right)$
Similarly angle between $i + j + k$ and $j$ is $\beta = {\cos ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} \right)$ and between $i + j + k$ and
$k$ is $\gamma = {\cos ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} \right)\,.$
Hence $\alpha = \beta = \gamma .$
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$a x+y=0$
$x+(a+10) y=0$
$(1)$ $a+b=3$
$(2)$ $\operatorname{det}\left(\operatorname{adj} M ^2\right)=81$
$(3)$ $(\operatorname{adj} M)^{-1}+\operatorname{adj} M^{-1}=-M$
$(4)$ If $M \left[\begin{array}{l}\alpha \\ \beta \\ \gamma\end{array}\right]=\left[\begin{array}{l}1 \\ 2 \\ 3\end{array}\right]$, then $\alpha-\beta+\gamma=3$
$\begin{bmatrix}0&0\\0&0\end{bmatrix}$
$\begin{bmatrix}0&0&0\\0&0&0\end{bmatrix}$
$\begin{bmatrix}0&0\\0&0\\0&0\end{bmatrix}$
$\begin{bmatrix}0\\0\\0\end{bmatrix}$