MCQ
If $\theta$ be the angle between any two vectors $\bar{a}$ and $\bar{b}$, then $|\vec{a} \cdot \vec{b}|=|\vec{a} \times \vec{b}|$, when $\theta$ is equal to
- A$\frac{\pi}{6}$
- ✓$\frac{\pi}{4}$
- C$\frac{\pi}{2}$
- D${\pi}$
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