MCQ
If $\theta$ be the angle between the unit vectors $ a$ and $b$, then $\cos \frac{\theta }{2} = $
- A$\frac{1}{2}\,|a - b|$
- ✓$\frac{1}{2}\,|a + b|$
- C$\frac{{|a - b|}}{{|a + b|}}$
- D$\frac{{|a + b|}}{{|a - b|}}$
or $|a + b{|^2} = 2.2{\cos ^2}\frac{\theta }{2} \Rightarrow \cos \frac{\theta }{2} = \frac{1}{2}|a + b|.$
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