MCQ
If $\theta$ be the angle between the unit vectors $ a$  and $b$, then $\cos \frac{\theta }{2} = $
  • A
    $\frac{1}{2}\,|a - b|$
  • $\frac{1}{2}\,|a + b|$
  • C
    $\frac{{|a - b|}}{{|a + b|}}$
  • D
    $\frac{{|a + b|}}{{|a - b|}}$

Answer

Correct option: B.
$\frac{1}{2}\,|a + b|$
b
(b) $(a + b).(a + b) = \,|a{|^2} + |b{|^2} + \,2a\,.\,b$

or $|a + b{|^2} = 2.2{\cos ^2}\frac{\theta }{2} \Rightarrow \cos \frac{\theta }{2} = \frac{1}{2}|a + b|.$

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