MCQ
If two angles are complementary and one angle is $10^\circ $ greater than the other, then the smaller angle of the two is:
- ✓$40^\circ$
- B$50^\circ $
- C$90^\circ$
- D$180^\circ$
$ x^\circ = (90^\circ - x^\circ ) + 10^\circ$
$\Rightarrow 2x^\circ = 100^\circ $
$\Rightarrow x^\circ = 50^\circ$
$\Rightarrow 90^\circ - x^\circ = 40^\circ .$
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