MCQ
If two angles in a triangle are $40^\circ $ and $60^\circ $, then the third angle is:
- A$90^\circ$
- ✓$80^\circ$
- C$70^\circ$
- D$60^\circ$
Let the third angle be $x$ Sum of angles $= 180^\circ 40^\circ + 60^\circ + x = 180^\circ 100^\circ + x = 180^\circ $
$\Rightarrow x = 80^\circ $
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