MCQ
If two different non-axial $d-$ orbitals having $'xz'$ nodal plane form $\pi$ -bond  by overlapping each other, then internuclear axis will be
  • A
    $x$
  • B
    $y$
  • C
    $z$
  • D
    They don't form $\pi$ -bond

Answer

$(d)$ Two different non-axial $d-$ orbitals will lie in planes perpendicular to each  other hence, such $d-$ orbital will not form $\pi$ -bond.

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