The sum of their probabilities must be equal to 1.
C
(a) and (b) both are correct.
D
None of the above is correctIf two. events are independent, then.
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D
None of the above is correctIf two. events are independent, then.
Let A and B are two independent events, Then,
$\text{P}(\text{A}\cap\text{B})=\text{P(A)}\times\text{P(B)}$
As, $\text{P}(\text{A}\cap\text{B})\neq0\text{ or }\text{P(A)}+\text{P(B)}\neq1$
So, both are neither mutually exclisive nor their sum of probability is 1.
Hence, the correct alternative is option (d).
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