- A3
- B4
- C5
- D8
solution:
Explanation: We know that arithmetic mean of two numbers is given by the average of two numbers i.e. A.M.
$\frac{(2+6)}{2}=\frac{8}{2}=4.$
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A triangle ABC is right angled at A has points A and B as (2, 3) and (0, -1) respectively. If BC = 5, then point C may be:
If sets A and B are defined as $\text{A}=\Big\{(\text{x},\text{y})|\text{y}=\frac{1}{\text{x}},0\neq\text{x}\in\text{R}\Big\}\ \text{B}=\{(\text{x},\text{y})|\text{y}=-\text{x},\text{x}\in\text{R}\},$ then
$\text{A}\cap\text{B}=\text{A}$
$\text{A}\cap\text{B}=\text{B}$
$\text{A}\cap\text{B}=\phi$
$\text{A}\cup\text{B}=\text{A}$
If $\text{f(z)}=\frac{7-\text{z}}{1-\text{z}^2},$ where z = 1 + 2i, then |f(z)| is:
$\frac{|\text{z}|}{2}$
$|\text{z}|$
$2|\text{z}|$
None of these