$\Rightarrow \cos \theta = - \frac{1}{2} \Rightarrow \theta = \frac{{2\pi }}{3}$

${y_1} = {10^{ - 6}}\sin [100\,t + (x/50) + 0.5]m$
${y_2} = {10^{ - 6}}\cos \,[100\,t + (x/50)]m$
where $ x$ is expressed in metres and $t$ is expressed in seconds, is approximately .... $ rad$
