MCQ
If uncertainty in position and momentum are equal, then uncertainty in velocity is
- A$\frac{1}{m}$ $ \sqrt{\frac{h}{\pi}}$
- B$\sqrt{\frac{h}{\pi}}$
- ✓$\frac{1}{2m} \sqrt{\frac{h}{\pi}}$
- D$\sqrt{\frac{h}{2 \pi}}$
$\Delta x . \Delta p=\frac{h}{4 \pi}$
$\Delta x=\Delta p(\Delta x=$ uncertainty in position)
$(\Delta p)^{2}=\frac{h}{4 \pi} \quad(\Delta p=m \times \Delta v)$
$m^{2} \Delta v^{2}=\frac{h}{4 \pi} \quad m=m a s s$
$\Delta v^{2}=\frac{h}{m^{2} 4 \pi}$
$\Delta v=\frac{1}{2 m} \sqrt{\frac{h}{\pi}}$
$\Delta v=$ uncertinty in velocity)
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$(i)$ $6C(s) + 3{H_2}(g) \to {C_6}{H_6}(l);\,\Delta H = + 45.9\,kJ$
$(ii)$ ${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(l);\,\Delta H = - 285.9\,kJ$
$(iii)$ $C(s) + {O_2}(g) \to C{O_2}(g);\,\Delta H = - 393.5\,kJ$
........$kJ$