MCQ
If $V$ be the accelerating voltage, then the maximum frequency of continuous $X-$ rays is given by
- A$\frac{{eh}}{V}$
- B$\frac{{hV}}{e}$
- ✓$\frac{{eV}}{h}$
- D$\frac{h}{{eV}}$
✓
Answer
Correct option: C.
$\frac{{eV}}{h}$
c
(c) $E = eV = h{\nu _{\max }}\, \Rightarrow \,{\nu _{\max }} = \frac{{eV}}{h}$
(c) $E = eV = h{\nu _{\max }}\, \Rightarrow \,{\nu _{\max }} = \frac{{eV}}{h}$
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