MCQ
If $v$ is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency $n$
- ✓$\frac{v}{{4n}}$
- B$\frac{v}{{2n}}$
- C$\frac{{2n}}{v}$
- D$\frac{{4n}}{v}$
i.e., $n = \frac{v}{{4l}}$==> $l = \frac{v}{{4n}}.$
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