Question
If $\vec{\text{a}}=4\hat{\text{i}}+3\hat{\text{j}}+\hat{\text{k}}$ and $\vec{\text{b}}=\hat{\text{i}}-2\hat{\text{k}},$ then find $\big|2\hat{\text{b}}\times\vec{\text{a}}\big|.$
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$\frac{\text{x}-5}{5\lambda+2}=\frac{2-\text{y}}{5}=\frac{1-\text{z}}{-1},\frac{\text{x}}{1}=\frac{2\text{y}+1}{4\lambda}=\frac{1-\text{z}}{-3}$