MCQ
If $\vec{a}+\vec{b}=\hat{i}$ and $\vec{a}=2 \hat{i}-2 \hat{j}+2 \hat{k}$, then $|\vec{b}|$ equals:
  • A
    $\sqrt{14}$
  • $3$
  • C
    $\sqrt{12}$
  • D
    $\sqrt{17}$

Answer

Correct option: B.
$3$
$\text {Given, } \hat{a}+\hat{b}=\hat{i}  $ and $ \vec{a}=2 \hat{i}-2 \hat{j}+2 \hat{k}$
$\Rightarrow 2 \hat{i}-2 \hat{j}+2 \hat{k}+\vec{b}=\hat{i} $
$\Rightarrow \vec{b}=\hat{i}-(2 \hat{i}-2 \hat{j}+2 \hat{k})$
$\Rightarrow -\hat{i}+2 \hat{j}-2 \hat{k}$
$\therefore|\vec{b}|=\sqrt{(-1)^2+(2)^2+(-2)^2}$
$=\sqrt{1+4+4}$
$=\sqrt{9}$
$=3$

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