MCQ
If $\vec{\text{a}}$ be the position vector whose tip is $(5, -3)$ find the coordinates of a point $B$ such that $\vec{\text{AB}}=\vec{\text{a}}$ the coordinates of $A$ being $(4, -1):$
- ✓$(9, -4)$
- B$(-9, -4)$
- C$(9, 4)$
- DNone of these
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$\left|\begin{array}{ccc}\cos ^{2} x & 1+\sin ^{2} x & \sin 2 x \\ 1+\cos ^{2} x & \sin ^{2} x & \sin 2 x \\ \cos ^{2} x & \sin ^{2} x & 1+\sin 2 x\end{array}\right|$.
Then the ordered pair $( m , M )$ is equal to
$A\left[ {\begin{array}{*{20}{c}}
1&2&3 \\
0&2&3 \\
0&1&1
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
0&0&1 \\
1&0&0 \\
0&1&0
\end{array}} \right]$ Then $A^{-1}$ is