MCQ
If vectors satisfy the condition $|a - c| = |b - c|$, then $(b - a)\,.\,\left( {c - \frac{{a + b}}{2}} \right)$ is equal to
  • $0$
  • B
    $-1$
  • C
    $1$
  • D
    $2$

Answer

Correct option: A.
$0$
a
(a) $(b - a)\,.\,\left( {c - \frac{{a + b}}{2}} \right) = b\,.\,c - b\,.\,\left( {\frac{{a + b}}{2}} \right)\, - a\,.\,c + \frac{a}{2}(a + b)$

and $|a - c|\, = \,|b - c|$ $ \Rightarrow $ $\,|a - c{|^2}\, = \,|b - c{|^2}$

$\therefore  a + b = 2c$

Therefore, $(b - a).\,\left( {c - \frac{{a + b}}{2}} \right) = 0.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free