MCQ
If vectors satisfy the condition $|a - c| = |b - c|$, then $(b - a)\,.\,\left( {c - \frac{{a + b}}{2}} \right)$ is equal to
- ✓$0$
- B$-1$
- C$1$
- D$2$
and $|a - c|\, = \,|b - c|$ $ \Rightarrow $ $\,|a - c{|^2}\, = \,|b - c{|^2}$
$\therefore a + b = 2c$
Therefore, $(b - a).\,\left( {c - \frac{{a + b}}{2}} \right) = 0.$
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