MCQ
If vectors $(\text{x}-2)\ \vec{\text{a}}+\vec{\text{b}}$ and $(2\text{x}+1)\ \vec{\text{a}}-\vec{\text{b}}$ are parallel then x:
- ✓$\frac{1}{3}$
- B$3$
- C$-3$
- D$\frac{-1}{3}$
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$3 x-y-z $$ =0 $, $-3 x+z $$ =0 $, $-3 x+2 y+z $$ =0 .$
Then the number of such points for which $x^2+y^2+z^2 \leq 100$ is