MCQ
If wavelength of photon is $2.2 \times {10^{ - 11}}$ $m$, $h = 6.6 \times {10^{ - 34}}$ $J-sec$, then momentum of photon is
  • $3 \times {10^{ - 23}}\,kg\,m{s^{ - 1}}$
  • B
    $3.33 \times {10^{22}}\,kg\,m{s^{ - 1}}$
  • C
    $1.452 \times {10^{ - 44}}\,kg\,m{s^{ - 1}}$
  • D
    $6.89 \times {10^{43}}\,kg\,m{s^{ - 1}}$

Answer

Correct option: A.
$3 \times {10^{ - 23}}\,kg\,m{s^{ - 1}}$
a
(a) $p = \frac{h}{\lambda } = \frac{{6.6 \times {{10}^{ - 34}}}}{{2.2 \times {{10}^{ - 11}}}} = 3 \times {10^{ - 23}}\,kg\,m{s^{ - 1}}$

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