MCQ
If we plot a graph between $\log \,K$ and $\frac{1}{T}$ by Arrhenius equation, the slope is
- A$ - \frac{{{E_a}}}{R}$
- B$ + \frac{{{E_a}}}{R}$
- ✓$ - \frac{{{E_a}}}{{2.303\,R}}$
- D$ + \frac{{{E_a}}}{{2.303\,R}}$
✓
Answer
Correct option: C.
$ - \frac{{{E_a}}}{{2.303\,R}}$
c
$\ln \,\,K = \ln $ $ - \frac{{{E_a}}}{{RT}}$ is Arrhenius equation.
$\ln \,\,K = \ln $ $ - \frac{{{E_a}}}{{RT}}$ is Arrhenius equation.
Thus plots of ln $K$ vs $1/T $ will give slope $ = - {E_a}/RT$ or $ - {E_a}/2.303R$.
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