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3. Chemical kinetics — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistry3. Chemical kinetics1 Mark
MCQ
If we plot a graph between $\log \,K$  and $\frac{1}{T}$ by Arrhenius equation, the slope is
  • A
    $ - \frac{{{E_a}}}{R}$
  • B
    $ + \frac{{{E_a}}}{R}$
  • ✓
    $ - \frac{{{E_a}}}{{2.303\,R}}$
  • D
    $ + \frac{{{E_a}}}{{2.303\,R}}$
✓

Answer

Correct option: C.
$ - \frac{{{E_a}}}{{2.303\,R}}$
c
$\ln \,\,K = \ln $ $ - \frac{{{E_a}}}{{RT}}$ is Arrhenius equation.

Thus plots of ln $K$ vs $1/T $ will give slope $ = - {E_a}/RT$ or $ - {E_a}/2.303R$.

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