MCQ
If $x - 2$ is a factor of $x^2 + 3ax - 2a$, then $a =$
- A$2$
- B$-2$
- C$1$
- ✓$-1$
Let $p(x) = x^2 + 3ax - 2a$ be the given polynomial.
$x - 2$ is a factor of $p(x).$
Thus,
$p(2) = 0$
$(2)^2 + 3a × 2 - 2a = 0$
$4 + 4a = 0$
$a = -1$
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