Rajasthan BoardEnglish MediumSTD 9MATHSPolynomials1 Mark
Question
If $x + 2$ is a factor ofm $x^2 + mx + 14$ then $m =$
✓
Answer
Firstly, we will divide $x^2 + mx + 14\ by\ x + 2$
When we divide them remainder comes to be $18 - 2\ m ....(i)$
Since $x + 2$ is a factor of $x^2 + mx + 14$
Therefore remainder should be zero $....(ii)$
From $1$ and $2$
$18 - 2\ m = 0$
$2\ m = 18$
$m = 9$
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