Download App

Relations and Functions — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsRelations and Functions1 Mark
Question
If $(\text{x}-2, \text{y}+5)=\big(-2, \frac{1}{3}\big)$ are two equal ordered pairs, then $\text{x}=4, \text{y}=\frac{-14}{3}.$ 
✓

Answer

False.
Solution:
We have, $(\text{x}-2, \text{y}+5)=\big(-2, \frac{1}{3}\big)$
$\Rightarrow\text{x}-2=-2, \text{y}+5=\frac{1}{3}$
$\Rightarrow\text{x}=0, \text{y}=\frac{-14}{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "True False[1 Marks ]" from Relations and Functions→Relations and Functions — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

State whether the statements are True or False.
The probability of an occurrence of event A is 0.7 and that of the occurrence of event B is .3 and the probability of occurrence of both is 0.4
→
Cartesian product of sets A and B is $A \times B =\{(a, b)$ : $a \in A, b \in B\}$
→
Let $\text{A}=\{\phi,\{\phi\},1\{1,\phi\},2\}.$ Then the statement is true?
$2\subset\text{A}.$
→
If the sum of n terms of a sequence is quadratic expression, then it always represents an $A.P.$
→
The straight line 5x + 4y = 0 passes through the point of intersection of the straight lines x + 2y - 10 = 0 and 2x + y + 5 = 0.
→
There are $12$ points in a plane of which $5$ points are collinear, then the number of lines obtained by joining these points in pairs is $^{12}C_2 – ^5C_2 .$
→
The given statements is corect? Write a correct form of the given incorrect statements.
{x : x + 3 = 3} = $\phi$
→
If $\log _x a, a^{x / 2}$ and $\log _b x$ are in geometric progression, then the value of $x$ is $\log _a\left(\log _b a\right)$.
→
If $a$ and $b$ are the roots of equation $x^2+x+1=0$, then $a^2+b^2=-1$.
→
If $\alpha$ and $\beta$ are the roots of the equation $4 x^2+3 x+$ $7=0$, then $\frac{1}{\alpha}+\frac{1}{\beta}$ is equal to $\frac{3}{7}$.
→