MCQ
If $x - 3$ is a factor of $x^2 - ax - 15,$ then $a =$
- ✓$-2$
- B$5$
- C$-5$
- D$3$
$x - 3$ is a factor of $x^2 - ax - 15,$
then at $x = 3,$
$x^2 - ax - 15 = 0$
$i.e. (3)^2 - a(3) - 15 = 0$
$9 - 3a - 15 = 0$
$a = -2$
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