MCQ
If $x = a{\cos ^3}\theta ,y = b{\sin ^3}\theta ,$ then
  • A
    ${\left( {\frac{a}{x}} \right)^{2/3}} + {\left( {\frac{b}{y}} \right)^{2/3}} = 1$
  • B
    ${\left( {\frac{b}{x}} \right)^{2/3}} + {\left( {\frac{a}{y}} \right)^{2/3}} = 1$
  • ${\left( {\frac{x}{a}} \right)^{2/3}} + {\left( {\frac{y}{b}} \right)^{2/3}} = 1$
  • D
    ${\left( {\frac{x}{b}} \right)^{2/3}} + {\left( {\frac{y}{a}} \right)^{2/3}} = 1$

Answer

Correct option: C.
${\left( {\frac{x}{a}} \right)^{2/3}} + {\left( {\frac{y}{b}} \right)^{2/3}} = 1$
c
(c) ${\left( {\frac{x}{a}} \right)^{1/3}} = \cos \,\theta ,\,\,{\left( {\frac{y}{b}} \right)^{1/3}} = \sin \theta $

Now square and add.

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