MCQ
If $x = a{\cos ^3}\theta ,y = b{\sin ^3}\theta ,$ then
  • A
    ${\left( {\frac{a}{x}} \right)^{2/3}} + {\left( {\frac{b}{y}} \right)^{2/3}} = 1$
  • B
    ${\left( {\frac{b}{x}} \right)^{2/3}} + {\left( {\frac{a}{y}} \right)^{2/3}} = 1$
  • ${\left( {\frac{x}{a}} \right)^{2/3}} + {\left( {\frac{y}{b}} \right)^{2/3}} = 1$
  • D
    ${\left( {\frac{x}{b}} \right)^{2/3}} + {\left( {\frac{y}{a}} \right)^{2/3}} = 1$

Answer

Correct option: C.
${\left( {\frac{x}{a}} \right)^{2/3}} + {\left( {\frac{y}{b}} \right)^{2/3}} = 1$
c
(c) ${\left( {\frac{x}{a}} \right)^{1/3}} = \cos \,\theta ,\,\,{\left( {\frac{y}{b}} \right)^{1/3}} = \sin \theta $

Now square and add.

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$(A)$ $\frac{1}{12} n(n+1)\left(3 n^2-n+1\right)$

$(B)$ $\frac{1}{12} n(n+1)\left(3 n^2+n+2\right)$

$(C)$ $\frac{1}{2} n\left(2 n^2-n+1\right)$

$(D)$ $\frac{1}{3}\left(2 n^3-2 n+3\right)$

$2.$  $\mathrm{T}_{\mathrm{T}}$ is always

$(A)$ an odd number $(B)$ an even number

$(C)$ a prime number $(D)$ a composite number

$3.$  Which one of the following is a correct statement?

$(A)$ $Q_1, Q_2, Q_3, \ldots$ are in $A.P.$ with common difference $5$

$(B)$ $\mathrm{Q}_1, \mathrm{Q}_2, \mathrm{Q}_3, \ldots$ are in $A.P.$ with common difference $6$

$(C)$ $\mathrm{Q}_1, \mathrm{Q}_2, \mathrm{Q}_3, \ldots$ are in $A.P.$ with common difference $11$

$(D)$ $Q_1=Q_2=Q_3=\ldots$

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