MCQ
If x be any integer different from zero and m, n be any integers, then $(x^m)^n$ is equal to:
  • A
    $\text{x}^{\text{m}+\text{n}}$
  • $\text{x}^{\text{mn}}$
  • C
    $\text{x}^{\frac{\text{m}}{\text{n}}}$
  • D
    $\text{x}^{\text{m}-\text{n}}$

Answer

Correct option: B.
$\text{x}^{\text{mn}}$
B.  $\text{x}^{\text{mn}}$
Solution:
Using law of exponents, $(\text{a}^{\text{m}})^{\text{n}}=(\text{a})^{\text{m}\times\text{n}}$ [$\because$ a is non-zero integer]
Similaly,
$(\text{x}^{\text{m}})^{\text{n}}=(\text{x})^{\text{m}\times\text{n}}$
$=(\text{x})^\text{mn}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free