MCQ
If $\text{x}+\frac{1}{\text{x}}=2,$ then $\text{x}^3+\frac{1}{\text{x}^3}=$
  • A
    8
  • B
    14
  • C
    64
  • D
    2

Answer

  1. 2
    Solution:
    On cubing we get
    $\Big(\text{x}+\frac{1}{\text{x}}\Big)^3=\text{x}^3+\Big(\frac{1}{\text{x}^3}\Big)+3\text{x}\times\frac{1}{\text{x}}\Big(\text{x}+\frac{1}{\text{x}}\Big)$
    $\Rightarrow2^3=\text{x}^3+\Big(\frac{1}{\text{x}^3}\Big)+3\times2$
    $\Rightarrow\text{3}^3+\Big(\frac{1}{\text{x}^3}\Big)=8-6$
    $\Rightarrow\text{x}^3+\Big(\frac{1}{\text{x}^3}\Big)=2$

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