Question
If $X$ has Poisson distribution with parameter $m$, such that
$\frac{P(X=x+1)}{P(X=x)}=\frac{m}{x+1}$
find probabilities $P(X=1)$ and $P(X=2)$, when $X$ follows Poisson distribution with $m =2$ and $P ( X =0)=0.1353$.
$\frac{P(X=x+1)}{P(X=x)}=\frac{m}{x+1}$
find probabilities $P(X=1)$ and $P(X=2)$, when $X$ follows Poisson distribution with $m =2$ and $P ( X =0)=0.1353$.