MCQ
If $X$ is a square matrix of order $ 3 × 3$ and $\lambda $ is a scalar, then adj ($\lambda X)$ is equal to
- A$\lambda \,adjX$
- B${\lambda ^3}adj\,X$
- ✓${\lambda ^2}adj\,X$
- D${\lambda ^4}adj\,X$
Here $n = 3$
$\therefore$ $adj(\lambda X) = {\lambda ^{3 - 1}}(adj\,X)$
$adj(\lambda X) = {\lambda ^2}(adj\,X)$.
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