MCQ
If $x \propto {t^{5/2}}$ , then
- A$v \propto {t^{3/2}}$
- B$a \propto \sqrt t $
- ✓both$ (A)$ and $(B)$
- D$v \propto \sqrt t $
✓
Answer
Correct option: C.
both$ (A)$ and $(B)$
c
Given $x \propto t^2 \quad \Rightarrow x= Kt ^2 \quad$ where $K = constant$
Given $x \propto t^2 \quad \Rightarrow x= Kt ^2 \quad$ where $K = constant$
$\therefore$ Velocity of the particle $v =\frac{ dx }{ dt }=2 Kt$
$\therefore$ Acceleration of the particle $a =\frac{ dv }{ dt }=2 K = constant$
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