MCQ
If $x = \sqrt {7 + 4\sqrt 3 } ,$ then $x + \frac{1}{x} = $
- ✓$4$
- B$6$
- C$3$
- D$2$
$\therefore$ $\frac{1}{x} = \frac{1}{{\sqrt {7 + 4\sqrt 3 } }} = \frac{{\sqrt {7 - 4\sqrt 3 } }}{{\sqrt {7 + 4\sqrt 3 } .\sqrt {7 - 4\sqrt 3 } }} = \sqrt {7 - 4\sqrt 3 } $
$\therefore$ $x + \frac{1}{x} = \sqrt {7 + 4\sqrt 3 } + \sqrt {7 - 4\sqrt 3 } $
$ = (\sqrt 3 + 2) + (2 - \sqrt 3 ) = 4$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
($1$) The radius of the circle $C$ is. . . . . .
($2$) The value of $\alpha$ is. . . . .
Given the answer or qution ($1$) and ($2$)