MCQ
If $x + y = 1$, then $\sum\limits_{r = 0}^n {{r^2}{\,^n}{C_r}{x^r}{y^{n - r}}} $ equals
- A$nxy$
- B$nx(x + yn)$
- ✓$nx(nx + y)$
- DNone of these
$\sum\limits_{r = 0}^n {{r^2}{\,^n}{C_r}{x^r}{y^{n - r}}} $
$ = \sum\limits_{r = 0}^n {[r(r - 1) + r]{\,^n}} {C_r}{x^r}{y^{n - r}}$
$ = \sum\limits_{r = 0}^n {r(r - 1){\,^n}} {C_r}{x^r}{y^{n - r}} + \sum\limits_{r = 0}^n {{r^n}{C_r}{x^r}{y^{n - r}}} $
$ = \sum\limits_{r = 2}^{n - 2} {r(r - 1)\frac{n}{r}.\frac{{n - 1}}{{r - 1}}{\,^{n - 2}}{C_{r - 2}}{x^2}{x^{r - 2}}{y^{n - r}}} $ $ + \sum\limits_{r = 1}^{n - 1} {r\frac{n}{r}{\,^{n - 1}}{C_{r - 1}}x\,\,{x^{r - 1}}{y^{n - r}}} $
$ = n(n - 1){x^2}\sum\limits_{r = 2}^{n - 2} {{\,^{n - 2}}{C_{r - 2}}{x^{r - 2}}{y^{(n - 2) - (r - 2)}}} $ $+ nx\sum\limits_{r = 2}^{n - 1} {{\,^{n - 1}}{C_{r - 1}}{X^{r - 1}}{y^{(n - 1) - (r - 1)}}}$
$ = n(n - 1){x^2}{(x + y)^{n - 2}} + nx{(x + y)^{n - 1}}$
$ = n(n - 1){x^2} + nx,\,\,\,\,\,(\because x + y = 1)$
$ = nx(nx - x + 1) = nx(nx + y)\,,\,\,(\because x + y = 1)$
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| $x_i$ | $0$ | $1$ | $5$ | $6$ | $10$ | $12$ | $17$ |
| $f_i$ | $3$ | $2$ | $3$ | $2$ | $6$ | $3$ | $3$ |