MCQ
If $[x]^2 - 5[x] + 6 = 0,$ where $[.]$ denote the greatest integer function$,$ then.
  • A
    $x \in [3, 4]$
  • B
    $x \in (2, 3]$
  • $x \in [2, 3]$
  • D
    $x \in [2, 4]$

Answer

Correct option: C.
$x \in [2, 3]$
We have $[x]^2 - 5[x] + 6 = 0$
$\Rightarrow [x]^2 - 3[x] 2[x] + 6 = 0$
$\Rightarrow [x]([x] - 3) -2([x] - 3) = 0$
$\Rightarrow ([x] - 3)([x] - 2) = 0$
$\Rightarrow [x] = 2, 3$
So$, x \in [2, 3]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free