MCQ
If $x=2 y+6$, then $x^3-8 y^3-36 x y=$
- A216
- B-216
- C36
- D-36
✓
Answer
A. 216
We have, $x=2 y+6$ or, $x-2 y-6=0$.
$\therefore$ $x^3-(-2 y)^3+(-6)^3=3 x(-2 y)(-6)$
$\Rightarrow$ $x^3-8 y^3-216=36 x y$ $\Rightarrow$ $x^3-8 y^3-36 x y=216$
We have, $x=2 y+6$ or, $x-2 y-6=0$.
$\therefore$ $x^3-(-2 y)^3+(-6)^3=3 x(-2 y)(-6)$
$\Rightarrow$ $x^3-8 y^3-216=36 x y$ $\Rightarrow$ $x^3-8 y^3-36 x y=216$
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