MCQ
If ${x^{2/3}} - 7{x^{1/3}} + 10 = 0,$ then $x = $
- A$\{125\}$
- B$\{8\}$
- C$\phi $
- ✓$\{125, 8\}$
${({x^{1/3}})^2} - 7({x^{1/3}}) + 10 = 0$
Let $a = {x^{1/3}}$, then it reduces to the equation
${a^2} - 7a + 10 = 0\,\, \Rightarrow (a - 5)(a - 2) = 0\,\,\, \Rightarrow a = 5,\,2$
Putting these values, we have ${a^3} = x\,\,\,\, \Rightarrow x = 125$ and $8.$
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$f(x) \rightarrow \frac{\lambda\left|x^{2}-5 x+6\right|}{\mu\left(5 x-x^{2}-6\right)}, x<2$
$\quad\quad\quad\quad e^{\frac{\tan (x-2)}{x-[x]}}, \quad x>2$
$\quad\quad\quad\quad \mu \quad\quad\quad\quad x=2$
Where $[x]$ is the greatest integer less than or equal to $x$. If $f$ is continuous at $x=2$, then $\lambda+\mu$ is equal to: