MCQ
If ${x^{2/3}} - 7{x^{1/3}} + 10 = 0,$ then $x = $
- A$\{125\}$
- B$\{8\}$
- C$\phi $
- ✓$\{125, 8\}$
${({x^{1/3}})^2} - 7({x^{1/3}}) + 10 = 0$
Let $a = {x^{1/3}}$, then it reduces to the equation
${a^2} - 7a + 10 = 0\,\, \Rightarrow (a - 5)(a - 2) = 0\,\,\, \Rightarrow a = 5,\,2$
Putting these values, we have ${a^3} = x\,\,\,\, \Rightarrow x = 125$ and $8.$
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