MCQ
If $x=a \sec \theta$ and $y=b \tan \theta$, then $b^2 x^2-a^2 y^2=$
- A$a b$
- B$a^2-b^2$
- C$a^2+b^2$
- ✓$a^2 b^2$
✓
Answer
Correct option: D.
$a^2 b^2$
D
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