MCQ
If $x=a t^2, y=2 a t$, then $\frac{d y}{d x}=$ __________ .
- A$\frac{y}{x}$
- B$\frac{x}{2 y}$
- ✓$\frac{y}{2 x}$
- D$\frac{x}{y}$
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$\left|\begin{array}{lll}(1+\alpha)^2 & (1+2 \alpha)^2 & (1+3 \alpha)^2 \\ (2+\alpha)^2 & (2+2 \alpha)^2 & (2+3 \alpha)^2 \\ (3+\alpha)^2 & (3+2 \alpha)^2 & (3+3 \alpha)^2\end{array}\right|=-648 \alpha$ ?
$(A)$ $-4$ $(B)$ $9$ $(C)$ $-9$ $(D)$ $4$