MCQ
If $xe^{xy}=y+e^{\sin 2x} ,$ then at $x=0, \, \frac{dy}{dx}$ is equal to -
- ✓$-1$
- B$1$
- C$0$
- D$2$
at $x=0$
$1+0=\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)_{\mathrm{x}=0}+2 \Rightarrow\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)_{\mathrm{x}=0}=-1$
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