If (x+i y)(2-3 i)=4+i then x+i y is equal to : - Vidyadip

MCQ

If $(x+i y)(2-3 i)=4+i$ then $x+i y$ is equal to :

A
$\frac{14}{13}+i \frac{5}{13}$
✓
$\frac{5}{13}+i \frac{14}{13}$
C
$\frac{-14}{13}+i \frac{5}{13}$
D
$\frac{5}{13}-i \frac{14}{13}$

✓

Answer

Correct option: B.

$\frac{5}{13}+i \frac{14}{13}$

(B)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from PART - 1 CH - 4 Complex Numbers and Quadratic Equations→PART - 1 CH - 4 Complex Numbers and Quadratic Equations — all question types→MATHS STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

If A and B are two sets such that n(A) = 17, n(B) = 23, n(A ∪ B) = 38, find n(A ∩ B):

Choose the correct answer.
The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is:

Equation of the circle through origin which cuts intercepts of length a and b on axes is:

If e₁ is the eccentricity of the conic 9x² + 4y² = 36 and e₂ is the eccentricity of the conic 9x² − 4y² = 36, then

$\text{e}_1^2-\text{e}_2^2=2$
$2<\text{e}_2^2-\text{e}_1^2<3$
$\text{e}_2^2-\text{e}_1^2=2$
$\text{e}_2^2-\text{e}_1^2>3$

The number of unsuccessful attempts that can be made by a thief to open a number lock having 3 rings in which each rings contains 6 numbers is:

Choose the correct answers:
The domain for which the functions defined by f(x) = 3x² – 1 and g(x) = 3 + x are equal is.

If x is an acute angle and $\text{x}=\frac{1}{\sqrt{7}},$ than the value of $\frac{\text{cosec}^2\text{x}-\sec^2\text{x}}{\text{cosec}^2\text{x}+\sec^2\text{x}}$ is:

$\frac{3}{4}$
$\frac{1}{2}$
$2$
$\frac{5}{4}$

Which of the following is a finite set :

If A × B = (5, 5), (5, 6), (5, 7), (8, 6), (8, 7), (8, 5), then the value A:

If $\text{a}=\cos\theta+\text{i}\sin\theta,$ then $\frac{1+\text{a}}{1-\text{a}}=$

$\cot\frac{\theta}{2}$
$\cot\theta$
$\text{i}\cot\frac{\theta}{2}$
$\text{i}\tan\frac{\theta}{2}$